Problem Solving Select Many GRE Sample Questions 2

GRE Problem Solving Select Many Sample Questions

GRE Problem Solving Select Many Sample Questions 1 | GRE Problem Solving Select Many Sample Questions 2 | GRE Problem Solving Select Many Sample Questions 3 | GRE Problem Solving Select Many Sample Questions 4 | GRE Problem Solving Select Many Sample Questions 5 | GRE Problem Solving Select Many Sample Questions 6 | GRE Problem Solving Select Many Sample Questions 7 | GRE Problem Solving Select Many Sample Questions 8 | GRE Problem Solving Select Many Sample Questions 9 | GRE Problem Solving Select Many Sample Questions 10

1. Question:

The distance between the points (4,p) and (1,0) is 5. Which of the following is the value of p? Indicate all such choices.

  • A. 4
  • B. -2
  • C. 2
  • D. 0
  • E. -4
Correct Answer: A and E

Explanation:

Distance between (4,p) and (1,0) = 5

Sqrt[(4-1)^2+(p-0)^2] = 5

Squaring both sides, we get

3^2+p^2= 5^2

9+p^2=25

p^2=25-9=16

p=sqrt(16) = 4, -4

Options A and E are true. All other options are false.

[p^2=p*p]




2. Question:

Which point is nearest to the origin? Indicate all correct options.

  • A. (-1, -1)
  • B. (1, 1)
  • C. (2,0)
  • D. (-2,2)
  • E. (0,2)
Correct Answer: A and B

Explanation:

The origin is the point (0,0)

The distance of the origin from the different points is

(-1,-1): Sqrt[(-1-0)^2+(-1-0)^2]= sqrt(1+1)= sqrt(2)

(1,1): Sqrt[(1-0)^2+(1-0)^2] = sqrt(1+1) = sqrt(2)

(2,0): Sqrt[(2-0)^2+(0-0)^2] = sqrt(4+0) = 2

(-2,2): Sqrt[(-2-0)^2+(2-0)^2] = sqrt(4+4) = sqrt(8)

(0,2): Sqrt[(0-0)^2+(2-0)^2] = sqrt(4) = 2

The points (-1,-1) and (1,1) are the closest.

Options A and B are true.

[4^2=4*4]




3. Question:

f(t) = 2t^2+2/t^2+5/t+5t. Which of the following is true? Indicate all correct choices.

  • A. f(1/t) = -f(t)
  • B. f(-t) = -f(t)
  • C. f(1/t) = f(t)
  • D. 1/f(t) = f(1/t)
  • E. f(1) = 14

[t^2=t*t]

Correct Answer: C and E

Explanation:

f(t)=2t^2+2/t^2+5/t+5t


-f(t) = -2t^2-2/t^2-5/t-5t


f(1/t) = 2(1/t)^2+2(1/1/t)^2+5/(1/t)+5(1/t)

= 2/t^2+2t^2+5t+5/t


f(-t)=2(-t)^2+2/(-t)^2+5/(-t)+5(-t)

= 2t^2+2/t^2-5/t-5t


1/f(t)=1/(2t^2+2/t^2+5/t+5t)


f(1/t) is not equal to -f(t). Option A is false.

f(-t) is not equal to -f(t). Option B is false.

f(1/t)=f(t). Option C is true.

1/f(t) is not equal to f(1/t). Option D is false.

f(1) = 2*1^2+2*1/1^2+5*1+5/1

= 2+2+5+5 = 14

Option E is true.

GRE Problem Solving Select Many Sample Questions

GRE Problem Solving Select Many Sample Questions 1 | GRE Problem Solving Select Many Sample Questions 2 | GRE Problem Solving Select Many Sample Questions 3 | GRE Problem Solving Select Many Sample Questions 4 | GRE Problem Solving Select Many Sample Questions 5 | GRE Problem Solving Select Many Sample Questions 6 | GRE Problem Solving Select Many Sample Questions 7 | GRE Problem Solving Select Many Sample Questions 8 | GRE Problem Solving Select Many Sample Questions 9 | GRE Problem Solving Select Many Sample Questions 10




Terms and Conditions


Information published in TestPrepPractice.net is provided for informational and educational purpose alone for deserving students, researchers and academicians. Though our volunteers take great amount of pain and spend significant time in validating the veracity of the information or study material presented here, we cannot be held liable for any incidental mistakes. All rights reserved. No information or study material in this web site can be reproduced or transmitted in any form, without our prior consent. However the study materials and web pages can be linked from your web site or web page for


  • Research

  • Education

  • Academic purposes

No permission is required to link any of the web page with educational information available in this web site from your web site or web page